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Triangle LOVE(拓扑排序)
阅读量:4970 次
发布时间:2019-06-12

本文共 1880 字,大约阅读时间需要 6 分钟。

Triangle LOVE

Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 65536/65536K (Java/Other)
Total Submission(s) : 40   Accepted Submission(s) : 27
Problem Description
Recently, scientists find that there is love between any of two people. For example, between A and B, if A don’t love B, then B must love A, vice versa. And there is no possibility that two people love each other, what a crazy world!
Now, scientists want to know whether or not there is a “Triangle Love” among N people. “Triangle Love” means that among any three people (A,B and C) , A loves B, B loves C and C loves A.
  Your problem is writing a program to read the relationship among N people firstly, and return whether or not there is a “Triangle Love”.
 
Input
The first line contains a single integer t (1 <= t <= 15), the number of test cases. For each case, the first line contains one integer N (0 < N <= 2000). In the next N lines contain the adjacency matrix A of the relationship (without spaces). A[sub]i,j[/sub] = 1 means i-th people loves j-th people, otherwise A[sub]i,j[/sub] = 0. It is guaranteed that the given relationship is a tournament, that is, A[sub]i,i[/sub]= 0, A[sub]i,j[/sub] ≠ A[sub]j,i[/sub](1<=i, j<=n,i≠j).
 
Output
For each case, output the case number as shown and then print “Yes”, if there is a “Triangle Love” among these N people, otherwise print “No”. Take the sample output for more details.
 
Sample Input
 
2 5 00100 10000 01001 11101 11000 5 01111 00000 01000 01100 01110
 
Sample Output
 
Case #1: Yes Case #2: No
 
Author
BJTU
 
Source
2012 Multi-University Training Contest 3
#include
#include
char map[2010][2010];int dre[2010];int main(){ int t,cot=0; scanf("%d",&t); while(t--) { int n,i,j,p; //memset(map,0,sizeof(map)); scanf("%d",&n); memset(dre,0,sizeof(dre)); getchar(); for(i=0;i

转载于:https://www.cnblogs.com/playboy307/p/5273826.html

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